My yard is 72 square feet and twice as long as it is wide.
l * w = 72 feet
l=2 * w
Substitute 2 * w in for l and you get
2 * w * w = 72 feet
w * w = 72 / 2
Simplify:
w^2 = 36
sqrt(w^2) = sqrt(36)
w = 6
l = 6*2 or 12
Perimeter = 6+6+12+12
Perimeter = 36 feet
width = w, length = l
wl = 72
l = 2w
w(2w) = 72
2(w^2) = 72
w^2 = 36
w = 6, l = 12
perimeter = 2w + 2l = 2(6) + 2(12) = 12 + 24 = 36 feet
References :
the answer from mamamia is only one of the many answers.
72 sq feet can also be a 72 ft x 1 ft rectangle. In this case, the total perimeter is 72 x 2 + 1 x 2 = 146 ft.
You usually see this kind of question in calculus class like what is the small perimeter to form rectangle of 72 sq ft.
(sorry I did not read your queston- just the title ) MamaMia is correct.
References :
l=2w
p=2l+2w
A=lw=2w*w=2w^2=72
w^2=36
w=6
l=2w=12
p=2*6+2*12=12+24=36′
References :
2x*x=72sqft
x=6ft
length=12ft
width=6ft
primeter
=2[12+6]
=36ft
References :
Area of Rectangle: A
Perimeter of Rectangle: P
width of rectangle: w
length of rectangle: L
To solve for P, we need to know L and w (length and width)
P = 2L + 2w
We do not know L and w, but we do know htat
Lw = 72
We also know that your yard is "twice as long as it is wide":
2w = L
Substitute this into the previous equation, and we have
2w² = 72
w² = 36
w = sqrt(36)
w = 6 ; therefore L = 12
Now we can solve for P:
P = 2(12) + 2(6) = 24 + 12 = 36 feet
References :
l * w = 72 feet
l=2 * w
Substitute 2 * w in for l and you get
2 * w * w = 72 feet
w * w = 72 / 2
Simplify:
w^2 = 36
sqrt(w^2) = sqrt(36)
w = 6
l = 6*2 or 12
Perimeter = 6+6+12+12
Perimeter = 36 feet
References :